Octal and binary literals are more appropriately converted to hex
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@ -122,11 +122,11 @@
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this.error("octal literal '" + number + "' must be prefixed with '0o'");
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}
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lexedLength = number.length;
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if (octalLiteral = /0o([0-7]+)/.exec(number)) {
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number = (parseInt(octalLiteral[1], 8)).toString();
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if (octalLiteral = /^0o([0-7]+)/.exec(number)) {
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number = '0x' + (parseInt(octalLiteral[1], 8)).toString(16);
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}
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if (binaryLiteral = /0b([01]+)/.exec(number)) {
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number = (parseInt(binaryLiteral[1], 2)).toString();
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if (binaryLiteral = /^0b([01]+)/.exec(number)) {
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number = '0x' + (parseInt(binaryLiteral[1], 2)).toString(16);
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}
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this.token('NUMBER', number);
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return lexedLength;
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@ -142,10 +142,10 @@ exports.Lexer = class Lexer
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else if /^0\d+/.test number
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@error "octal literal '#{number}' must be prefixed with '0o'"
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lexedLength = number.length
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if octalLiteral = /0o([0-7]+)/.exec number
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number = (parseInt octalLiteral[1], 8).toString()
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if binaryLiteral = /0b([01]+)/.exec number
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number = (parseInt binaryLiteral[1], 2).toString()
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if octalLiteral = /^0o([0-7]+)/.exec number
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number = '0x' + (parseInt octalLiteral[1], 8).toString 16
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if binaryLiteral = /^0b([01]+)/.exec number
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number = '0x' + (parseInt binaryLiteral[1], 2).toString 16
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@token 'NUMBER', number
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lexedLength
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