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healthcheck: do not interpret exit code 2 as "starting"

Instead reserve exit code 2 to be future proof, document that it should
not be used. Implementation-wise, it is considered as unhealthy, but
users should not rely on this as it may change in the future.

Signed-off-by: Tibor Vass <tibor@docker.com>
(cherry picked from commit 91e9f38313)
Signed-off-by: Tibor Vass <tibor@docker.com>
This commit is contained in:
Tibor Vass 2016-07-20 10:50:04 -07:00
parent bf024205b7
commit 0df31ff193
3 changed files with 2 additions and 24 deletions

View file

@ -41,7 +41,6 @@ const (
exitStatusHealthy = 0 // Container is healthy
exitStatusUnhealthy = 1 // Container is unhealthy
exitStatusStarting = 2 // Container needs more time to start
)
// probe implementations know how to run a particular type of probe.
@ -127,12 +126,10 @@ func handleProbeResult(d *Daemon, c *container.Container, result *types.Healthch
if result.ExitCode == exitStatusHealthy {
h.FailingStreak = 0
h.Status = types.Healthy
} else if result.ExitCode == exitStatusStarting && c.State.Health.Status == types.Starting {
// The container is not ready yet. Remain in the starting state.
} else {
// Failure (including invalid exit code)
h.FailingStreak++
if c.State.Health.FailingStreak >= retries {
if h.FailingStreak >= retries {
h.Status = types.Unhealthy
}
// Else we're starting or healthy. Stay in that state.

View file

@ -94,22 +94,6 @@ func TestHealthStates(t *testing.T) {
handleResult(c.State.StartedAt.Add(3*time.Second), 1)
expect("health_status: unhealthy")
// starting -> starting -> starting ->
// healthy -> starting (invalid transition)
reset(c)
handleResult(c.State.StartedAt.Add(20*time.Second), 2)
handleResult(c.State.StartedAt.Add(40*time.Second), 2)
if c.State.Health.Status != types.Starting {
t.Errorf("Expecting starting, but got %#v\n", c.State.Health.Status)
}
handleResult(c.State.StartedAt.Add(50*time.Second), 0)
expect("health_status: healthy")
handleResult(c.State.StartedAt.Add(60*time.Second), 2)
expect("health_status: unhealthy")
// Test retries
reset(c)

View file

@ -1524,10 +1524,7 @@ The possible values are:
- 0: success - the container is healthy and ready for use
- 1: unhealthy - the container is not working correctly
- 2: starting - the container is not ready for use yet, but is working correctly
If the probe returns 2 ("starting") when the container has already moved out of the
"starting" state then it is treated as "unhealthy" instead.
- 2: reserved - do not use this exit code
For example, to check every five minutes or so that a web-server is able to
serve the site's main page within three seconds: