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6fff845409
If the network is marked as external, don't use the namespace on it. Otherwise, it's not found. Signed-off-by: Vincent Demeester <vincent@sbr.pm>
56 lines
1.2 KiB
Go
56 lines
1.2 KiB
Go
package stack
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import (
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"golang.org/x/net/context"
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"github.com/docker/docker/api/types"
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"github.com/docker/docker/api/types/filters"
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"github.com/docker/docker/api/types/swarm"
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"github.com/docker/docker/client"
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)
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const (
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labelNamespace = "com.docker.stack.namespace"
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)
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func getStackLabels(namespace string, labels map[string]string) map[string]string {
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if labels == nil {
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labels = make(map[string]string)
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}
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labels[labelNamespace] = namespace
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return labels
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}
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func getStackFilter(namespace string) filters.Args {
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filter := filters.NewArgs()
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filter.Add("label", labelNamespace+"="+namespace)
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return filter
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}
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func getServices(
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ctx context.Context,
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apiclient client.APIClient,
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namespace string,
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) ([]swarm.Service, error) {
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return apiclient.ServiceList(
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ctx,
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types.ServiceListOptions{Filters: getStackFilter(namespace)})
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}
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func getStackNetworks(
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ctx context.Context,
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apiclient client.APIClient,
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namespace string,
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) ([]types.NetworkResource, error) {
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return apiclient.NetworkList(
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ctx,
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types.NetworkListOptions{Filters: getStackFilter(namespace)})
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}
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type namespace struct {
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name string
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}
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func (n namespace) scope(name string) string {
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return n.name + "_" + name
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}
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