56 lines
1.9 KiB
Ruby
56 lines
1.9 KiB
Ruby
require "rails_helper"
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module PaperTrail
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RSpec.describe Cleaner, versioning: true do
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after do
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PaperTrail.config.version_limit = nil
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end
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it "cleans up old versions" do
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PaperTrail.config.version_limit = 10
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widget = Widget.create
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100.times do |i|
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widget.update_attributes(name: "Name #{i}")
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expect(Widget.find(widget.id).versions.count).to be <= 11
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# 11 versions = 10 updates + 1 create.
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end
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end
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it "deletes oldest versions, when the database returns them in a different order" do
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epoch = DateTime.new(2017, 1, 1)
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widget = Timecop.freeze(epoch) { Widget.create }
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# Sometimes a database will returns records in a different order than
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# they were inserted. That's hard to get the database to do, so we'll
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# just create them out-of-order:
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(1..5).to_a.shuffle.each do |n|
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Timecop.freeze(epoch + n.hours) do
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PaperTrail::Version.create!(
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item: widget,
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event: "update",
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object: { "id" => widget.id, "name" => "Name #{n}" }.to_yaml
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)
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end
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end
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expect(Widget.find(widget.id).versions.count).to eq(6) # 1 create + 5 updates
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# Now, we've recreated the scenario where we can accidentally clean up
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# the wrong versions. Re-enable the version_limit, and trigger the
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# clean-up:
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PaperTrail.config.version_limit = 3
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widget.versions.last.send(:enforce_version_limit!)
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# Verify that we have fewer versions:
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expect(widget.reload.versions.count).to eq(4) # 1 create + 4 updates
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# Exclude the create, because the create will return nil for `#reify`.
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last_names = widget.versions.not_creates.map(&:reify).map(&:name)
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expect(last_names).to eq(["Name 3", "Name 4", "Name 5"])
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# No matter what order the version records are returned it, we should
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# always keep the most-recent changes.
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end
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end
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end
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