paper-trail-gem--paper_trail/spec/paper_trail/version_limit_spec.rb

56 lines
1.9 KiB
Ruby

# frozen_string_literal: true
require "spec_helper"
module PaperTrail
::RSpec.describe Cleaner, versioning: true do
after do
PaperTrail.config.version_limit = nil
end
it "cleans up old versions" do
PaperTrail.config.version_limit = 10
widget = Widget.create
100.times do |i|
widget.update(name: "Name #{i}")
expect(Widget.find(widget.id).versions.count).to be <= 11
# 11 versions = 10 updates + 1 create.
end
end
it "deletes oldest versions, when the database returns them in a different order" do
epoch = Date.new(2017, 1, 1)
widget = Widget.create(created_at: epoch)
# Sometimes a database will returns records in a different order than
# they were inserted. That's hard to get the database to do, so we'll
# just create them out-of-order:
(1..5).to_a.shuffle.each do |n|
PaperTrail::Version.create!(
created_at: epoch + n.hours,
item: widget,
event: "update",
object: { "id" => widget.id, "name" => "Name #{n}" }.to_yaml
)
end
expect(Widget.find(widget.id).versions.count).to eq(6) # 1 create + 5 updates
# Now, we've recreated the scenario where we can accidentally clean up
# the wrong versions. Re-enable the version_limit, and trigger the
# clean-up:
PaperTrail.config.version_limit = 3
widget.versions.last.send(:enforce_version_limit!)
# Verify that we have fewer versions:
expect(widget.reload.versions.count).to eq(4) # 1 create + 4 updates
# Exclude the create, because the create will return nil for `#reify`.
last_names = widget.versions.not_creates.map(&:reify).map(&:name)
expect(last_names).to eq(["Name 3", "Name 4", "Name 5"])
# No matter what order the version records are returned it, we should
# always keep the most-recent changes.
end
end
end