Speed up Levenshtein by 50% and reduce 97% of memory usage

Calculating -------------------------------------
             each_char   924.000  i/100ms
        each_codepoint     1.381k i/100ms
  -------------------------------------------------
             each_char      9.320k (¡Þ 5.1%) i/s -     47.124k
        each_codepoint     13.857k (¡Þ 3.6%) i/s -     70.431k

  Comparison:
        each_codepoint:    13857.4 i/s
             each_char:     9319.5 i/s - 1.49x slower

The full report can be found here:
  https://gist.github.com/yuki24/a80988f35aceac76f1d5
This commit is contained in:
Yuki Nishijima 2015-04-11 15:16:10 -07:00
parent 193297abc8
commit f7ba69436a
2 changed files with 10 additions and 4 deletions

View File

@ -14,10 +14,13 @@ module RailsGuides
d = (0..m).to_a
x = nil
str1.each_char.each_with_index do |char1,i|
# avoid duplicating an enumerable object in the loop
str2_codepoint_enumerable = str2.each_codepoint
str1.each_codepoint.with_index do |char1, i|
e = i+1
str2.each_char.each_with_index do |char2,j|
str2_codepoint_enumerable.with_index do |char2, j|
cost = (char1 == char2) ? 0 : 1
x = [
d[j+1] + 1, # insertion

View File

@ -267,10 +267,13 @@ module Rails
d = (0..m).to_a
x = nil
str1.each_char.each_with_index do |char1,i|
# avoid duplicating an enumerable object in the loop
str2_codepoint_enumerable = str2.each_codepoint
str1.each_codepoint.with_index do |char1, i|
e = i+1
str2.each_char.each_with_index do |char2,j|
str2_codepoint_enumerable.with_index do |char2, j|
cost = (char1 == char2) ? 0 : 1
x = [
d[j+1] + 1, # insertion