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Move spec/rubyspec to spec/ruby for consistency
* Other ruby implementations use the spec/ruby directory. [Misc #13792] [ruby-core:82287] git-svn-id: svn+ssh://ci.ruby-lang.org/ruby/trunk@59979 b2dd03c8-39d4-4d8f-98ff-823fe69b080e
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spec/ruby/library/csv/parse_spec.rb
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81
spec/ruby/library/csv/parse_spec.rb
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require File.expand_path('../../../spec_helper', __FILE__)
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require 'csv'
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describe "CSV.parse" do
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it "parses '' into []" do
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result = CSV.parse ''
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result.should be_kind_of(Array)
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result.should == []
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end
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it "parses '\n' into [[]]" do
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result = CSV.parse "\n"
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result.should == [[]]
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end
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it "parses 'foo' into [['foo']]" do
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result = CSV.parse 'foo'
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result.should == [['foo']]
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end
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it "parses 'foo,bar,baz' into [['foo','bar','baz']]" do
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result = CSV.parse 'foo,bar,baz'
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result.should == [['foo','bar','baz']]
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end
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it "parses 'foo,baz' into [[foo,nil,baz]]" do
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result = CSV.parse 'foo,,baz'
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result.should == [['foo',nil,'baz']]
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end
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it "parses '\nfoo' into [[],['foo']]" do
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result = CSV.parse "\nfoo"
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result.should == [[],['foo']]
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end
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it "parses 'foo\n' into [['foo']]" do
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result = CSV.parse "foo\n"
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result.should == [['foo']]
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end
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it "parses 'foo\nbar' into [['foo'],['bar']]" do
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result = CSV.parse "foo\nbar"
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result.should == [['foo'],['bar']]
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end
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it "parses 'foo,bar\nbaz,quz' into [['foo','bar'],['baz','quz']]" do
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result = CSV.parse "foo,bar\nbaz,quz"
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result.should == [['foo','bar'],['baz','quz']]
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end
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it "parses 'foo,bar'\nbaz' into [['foo','bar'],['baz']]" do
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result = CSV.parse "foo,bar\nbaz"
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result.should == [['foo','bar'],['baz']]
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end
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it "parses 'foo\nbar,baz' into [['foo'],['bar','baz']]" do
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result = CSV.parse "foo\nbar,baz"
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result.should == [['foo'],['bar','baz']]
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end
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it "parses '\n\nbar' into [[],[],'bar']]" do
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result = CSV.parse "\n\nbar"
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result.should == [[],[],['bar']]
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end
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it "parses 'foo' into [['foo']] with a separator of ;" do
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result = CSV.parse "foo", col_sep: ?;
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result.should == [['foo']]
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end
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it "parses 'foo;bar' into [['foo','bar']] with a separator of ;" do
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result = CSV.parse "foo;bar", col_sep: ?;
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result.should == [['foo','bar']]
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end
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it "parses 'foo;bar\nbaz;quz' into [['foo','bar'],['baz','quz']] with a separator of ;" do
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result = CSV.parse "foo;bar\nbaz;quz", col_sep: ?;
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result.should == [['foo','bar'],['baz','quz']]
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end
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end
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