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Move spec/rubyspec to spec/ruby for consistency
* Other ruby implementations use the spec/ruby directory. [Misc #13792] [ruby-core:82287] git-svn-id: svn+ssh://ci.ruby-lang.org/ruby/trunk@59979 b2dd03c8-39d4-4d8f-98ff-823fe69b080e
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spec/ruby/shared/rational/round.rb
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71
spec/ruby/shared/rational/round.rb
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require File.expand_path('../../../spec_helper', __FILE__)
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describe :rational_round, shared: true do
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before do
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@rational = Rational(2200, 7)
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end
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describe "with no arguments (precision = 0)" do
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it "returns an integer" do
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@rational.round.should be_kind_of(Integer)
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Rational(0, 1).round(0).should be_kind_of(Integer)
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Rational(124, 1).round(0).should be_kind_of(Integer)
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end
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it "returns the truncated value toward the nearest integer" do
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@rational.round.should == 314
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Rational(0, 1).round(0).should == 0
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Rational(2, 1).round(0).should == 2
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end
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it "returns the rounded value toward the nearest integer" do
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Rational(1, 2).round.should == 1
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Rational(-1, 2).round.should == -1
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Rational(3, 2).round.should == 2
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Rational(-3, 2).round.should == -2
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Rational(5, 2).round.should == 3
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Rational(-5, 2).round.should == -3
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end
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end
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describe "with a precision < 0" do
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it "returns an integer" do
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@rational.round(-2).should be_kind_of(Integer)
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@rational.round(-1).should be_kind_of(Integer)
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Rational(0, 1).round(-1).should be_kind_of(Integer)
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Rational(2, 1).round(-1).should be_kind_of(Integer)
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end
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it "moves the truncation point n decimal places left" do
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@rational.round(-3).should == 0
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@rational.round(-2).should == 300
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@rational.round(-1).should == 310
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end
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end
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describe "with a precision > 0" do
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it "returns a Rational" do
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@rational.round(1).should be_kind_of(Rational)
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@rational.round(2).should be_kind_of(Rational)
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Rational(0, 1).round(1).should be_kind_of(Rational)
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Rational(2, 1).round(1).should be_kind_of(Rational)
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end
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it "moves the truncation point n decimal places right" do
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@rational.round(1).should == Rational(3143, 10)
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@rational.round(2).should == Rational(31429, 100)
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@rational.round(3).should == Rational(157143, 500)
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Rational(0, 1).round(1).should == Rational(0, 1)
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Rational(2, 1).round(1).should == Rational(2, 1)
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end
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it "doesn't alter the value if the precision is too great" do
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Rational(3, 2).round(10).should == Rational(3, 2).round(20)
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end
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# #6605
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it "doesn't fail when rounding to an absurdly large positive precision" do
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Rational(3, 2).round(2_097_171).should == Rational(3, 2)
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end
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end
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end
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