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Fix Proc#<< spec

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[Bug #16406]
This commit is contained in:
Alan Wu 2019-12-30 18:13:55 -05:00
parent f1ea5d22dc
commit 3264a00958
1 changed files with 24 additions and 10 deletions
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34
spec/ruby/core/proc/compose_spec.rb
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@ -38,20 +38,34 @@ ruby_version_is "2.6" do
(f << g).lambda?.should == false (f << g).lambda?.should == false
end end
it "is a Proc when other is lambda" do ruby_version_is(''...'2.8') do
f = proc { |x| x * x } it "is a Proc when other is lambda" do
g = -> x { x + x } f = proc { |x| x * x }
g = -> x { x + x }
(f << g).is_a?(Proc).should == true (f << g).is_a?(Proc).should == true
(f << g).lambda?.should == false (f << g).lambda?.should == false
end
it "is a lambda when self is lambda" do
f = -> x { x * x }
g = proc { |x| x + x }
(f << g).is_a?(Proc).should == true
(f << g).lambda?.should == true
end
end end
it "is a lambda when self is lambda" do ruby_version_is('2.8') do
f = -> x { x * x } it "is a lambda when parameter is lambda" do
g = proc { |x| x + x } f = -> x { x * x }
g = proc { |x| x + x }
lambda_proc = -> x { x }
(f << g).is_a?(Proc).should == true (f << g).is_a?(Proc).should == true
(f << g).lambda?.should == true (f << g).lambda?.should == false
(f << lambda_proc).lambda?.should == true
end
end end
it "may accept multiple arguments" do it "may accept multiple arguments" do