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Fixed about ARGF.lineno

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[Bug #15823]
This commit is contained in:
Nobuyoshi Nakada 2019-05-05 14:32:45 +09:00
parent 84e71e9fc1
commit 374c8f4eba
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1 changed files with 10 additions and 2 deletions
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io.c
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@ -12393,13 +12393,21 @@ argf_block_call_line(ID mid, int argc, VALUE *argv, VALUE argf)
* a single file consisting of the concatenation of each named file. After
* the last line of the first file has been returned, the first line of the
* second file is returned. The +ARGF.filename+ and +ARGF.lineno+ methods can
* be used to determine the filename and line number, respectively, of the
* current line.
* be used to determine the filename of the current line and line number of
* the whole input, respectively.
*
* For example, the following code prints out each line of each named file
* prefixed with its line number, displaying the filename once per file:
*
* ARGF.each_line do |line|
* puts ARGF.filename if ARGF.file.lineno == 1
* puts "#{ARGF.file.lineno}: #{line}"
* end
*
* While the following code prints only the first file's name at first, and
* the contents with line number counted through all named files.
*
* ARGF.each_line do |line|
* puts ARGF.filename if ARGF.lineno == 1
* puts "#{ARGF.lineno}: #{line}"
* end