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Decide lambdaness of (f << g) using g (#2729)
* Deciding lambdaness of (f << g) using g * Use version guards for spec changes
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git
2019-12-31 07:48:31 +09:00
Merged-By: XrXr
3 changed files with 16 additions and 3 deletions
10
proc.c
10
proc.c
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@ -3386,8 +3386,14 @@ rb_proc_compose_to_left(VALUE self, VALUE g)
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procs[1] = g;
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args = rb_ary_tmp_new_from_values(0, 2, procs);
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GetProcPtr(self, procp);
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is_lambda = procp->is_lambda;
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if (rb_obj_is_proc(g)) {
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GetProcPtr(g, procp);
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is_lambda = procp->is_lambda;
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}
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else {
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VM_ASSERT(rb_obj_is_method(g) || rb_obj_respond_to(g, idCall, TRUE));
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is_lambda = 1;
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}
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proc = rb_proc_new(compose, args);
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GetProcPtr(proc, procp);
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@ -39,7 +39,8 @@ ruby_version_is "2.6" do
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double = proc { |x| x + x }
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(pow_2 << double).is_a?(Proc).should == true
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(pow_2 << double).lambda?.should == true
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ruby_version_is(''...'2.8') { (pow_2 << double).lambda?.should == true }
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ruby_version_is('2.8') { (pow_2 << double).lambda?.should == false }
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end
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it "may accept multiple arguments" do
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@ -1413,9 +1413,13 @@ class TestProc < Test::Unit::TestCase
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def test_compose_with_lambda
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f = lambda {|x| x * 2}
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g = lambda {|x| x}
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not_lambda = proc {|x| x}
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assert_predicate((f << g), :lambda?)
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assert_predicate((g >> f), :lambda?)
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assert_predicate((not_lambda << f), :lambda?)
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assert_not_predicate((f << not_lambda), :lambda?)
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assert_not_predicate((not_lambda >> f), :lambda?)
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end
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def test_compose_with_method
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@ -1427,6 +1431,7 @@ class TestProc < Test::Unit::TestCase
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assert_equal(6, (f << g).call(2))
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assert_equal(5, (f >> g).call(2))
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assert_predicate((f << g), :lambda?)
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end
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def test_compose_with_callable
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@ -1438,6 +1443,7 @@ class TestProc < Test::Unit::TestCase
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assert_equal(6, (f << g).call(2))
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assert_equal(5, (f >> g).call(2))
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assert_predicate((f << g), :lambda?)
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end
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def test_compose_with_noncallable
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