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[ruby/date] Fix Time#to_datetime before calendar reform

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Time is always in the proleptic Gregorian calendar.
Also DateTime#to_time should convert to the Gregorian calendar first,
before extracting its components.

https://bugs.ruby-lang.org/issues/18946#change-98527

https://github.com/ruby/date/commit/b2aee75248
This commit is contained in:
Nobuyoshi Nakada 2022-08-08 22:43:56 +09:00 committed by git
parent 43239b23b4
commit e07d450dea
2 changed files with 26 additions and 4 deletions
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13
ext/date/date_core.c
View file

@ -8811,7 +8811,7 @@ time_to_datetime(VALUE self)
ret = d_complex_new_internal(cDateTime,
nth, 0,
0, sf,
of, DEFAULT_SG,
of, GREGORIAN,
ry, m, d,
h, min, s,
HAVE_CIVIL | HAVE_TIME);
@ -8915,12 +8915,17 @@ date_to_datetime(VALUE self)
static VALUE
datetime_to_time(VALUE self)
{
volatile VALUE dup = dup_obj(self);
get_d1(self);
if (m_julian_p(dat)) {
self = d_lite_gregorian(self);
get_d1a(self);
dat = adat;
}
{
VALUE t;
get_d1(dup);
t = rb_funcall(rb_cTime,
rb_intern("new"),
7,

17
test/date/test_date_conv.rb
View file

@ -77,6 +77,11 @@ class TestDateConv < Test::Unit::TestCase
assert_equal([2004, 9, 19, 1, 2, 3, 456789],
[t.year, t.mon, t.mday, t.hour, t.min, t.sec, t.usec])
d = DateTime.new(1582, 10, 3, 1, 2, 3, 0) + 456789.to_r/86400000000
t = d.to_time.utc
assert_equal([1582, 10, 13, 1, 2, 3, 456789],
[t.year, t.mon, t.mday, t.hour, t.min, t.sec, t.usec])
if Time.allocate.respond_to?(:nsec)
d = DateTime.new(2004, 9, 19, 1, 2, 3, 0) + 456789123.to_r/86400000000000
t = d.to_time.utc
@ -100,6 +105,10 @@ class TestDateConv < Test::Unit::TestCase
t = Time.utc(2004, 9, 19, 1, 2, 3, 456789)
d = t.to_date
assert_equal([2004, 9, 19, 0], [d.year, d.mon, d.mday, d.day_fraction])
t = Time.utc(1582, 10, 13, 1, 2, 3, 456789)
d = t.to_date # using ITALY
assert_equal([1582, 10, 3, 0], [d.year, d.mon, d.mday, d.day_fraction])
end
def test_to_date__from_date
@ -136,6 +145,14 @@ class TestDateConv < Test::Unit::TestCase
[d.year, d.mon, d.mday, d.hour, d.min, d.sec,
d.sec_fraction, d.offset])
t = Time.utc(1582, 10, 13, 1, 2, 3, 456789)
d = t.to_datetime # using ITALY
assert_equal([1582, 10, 3, 1, 2, 3,
456789.to_r/1000000,
0],
[d.year, d.mon, d.mday, d.hour, d.min, d.sec,
d.sec_fraction, d.offset])
t = Time.now
d = t.to_datetime
require 'time'