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9e0075a3d9
iff means if and only if, but readers without that knowledge might assume this to be a spelling mistake. To me, this seems like exclusionary language that is unnecessary. Simply using "if and only if" instead should suffice.
36 lines
1.4 KiB
Ruby
36 lines
1.4 KiB
Ruby
require_relative '../../spec_helper'
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describe "Integer#anybits?" do
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it "returns true if and only if all the bits of the argument are set in the receiver" do
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42.anybits?(42).should == true
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0b1010_1010.anybits?(0b1000_0010).should == true
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0b1010_1010.anybits?(0b1000_0001).should == true
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0b1000_0010.anybits?(0b0010_1100).should == false
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different_bignum = (2 * bignum_value) & (~bignum_value)
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(0b1010_1010 | different_bignum).anybits?(0b1000_0010 | bignum_value).should == true
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(0b1010_1010 | different_bignum).anybits?(0b0010_1100 | bignum_value).should == true
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(0b1000_0010 | different_bignum).anybits?(0b0010_1100 | bignum_value).should == false
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end
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it "handles negative values using two's complement notation" do
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(~42).anybits?(42).should == false
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(-42).anybits?(-42).should == true
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(~0b100).anybits?(~0b1).should == true
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(~(0b100 | bignum_value)).anybits?(~(0b1 | bignum_value)).should == true
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end
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it "coerces the rhs using to_int" do
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obj = mock("the int 0b10")
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obj.should_receive(:to_int).and_return(0b10)
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0b110.anybits?(obj).should == true
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end
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it "raises a TypeError when given a non-Integer" do
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-> {
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(obj = mock('10')).should_receive(:coerce).any_number_of_times.and_return([42,10])
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13.anybits?(obj)
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}.should raise_error(TypeError)
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-> { 13.anybits?("10") }.should raise_error(TypeError)
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-> { 13.anybits?(:symbol) }.should raise_error(TypeError)
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end
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end
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