63 lines
2.2 KiB
Ruby
63 lines
2.2 KiB
Ruby
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require 'spec_helper'
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describe Gitlab::IssuableSorter, lib: true do
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let(:namespace1) { build(:namespace, id: 1) }
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let(:project1) { build(:project, id: 1, namespace: namespace1) }
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let(:project2) { build(:project, id: 2, path: "a", namespace: project1.namespace) }
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let(:project3) { build(:project, id: 3, path: "b", namespace: project1.namespace) }
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let(:namespace2) { build(:namespace, id: 2, path: "a") }
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let(:namespace3) { build(:namespace, id: 3, path: "b") }
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let(:project4) { build(:project, id: 4, path: "a", namespace: namespace2) }
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let(:project5) { build(:project, id: 5, path: "b", namespace: namespace2) }
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let(:project6) { build(:project, id: 6, path: "a", namespace: namespace3) }
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let(:unsorted) { [sorted[2], sorted[3], sorted[0], sorted[1]] }
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let(:sorted) do
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[build(:issue, iid: 1, project: project1),
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build(:issue, iid: 2, project: project1),
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build(:issue, iid: 10, project: project1),
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build(:issue, iid: 20, project: project1)]
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end
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it 'sorts references by a given key' do
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expect(described_class.sort(project1, unsorted)).to eq(sorted)
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end
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context 'for JIRA issues' do
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let(:sorted) do
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[ExternalIssue.new('JIRA-1', project1),
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ExternalIssue.new('JIRA-2', project1),
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ExternalIssue.new('JIRA-10', project1),
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ExternalIssue.new('JIRA-20', project1)]
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end
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it 'sorts references by a given key' do
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expect(described_class.sort(project1, unsorted)).to eq(sorted)
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end
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end
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context 'for references from multiple projects and namespaces' do
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let(:sorted) do
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[build(:issue, iid: 1, project: project1),
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build(:issue, iid: 2, project: project1),
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build(:issue, iid: 10, project: project1),
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build(:issue, iid: 1, project: project2),
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build(:issue, iid: 1, project: project3),
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build(:issue, iid: 1, project: project4),
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build(:issue, iid: 1, project: project5),
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build(:issue, iid: 1, project: project6)]
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end
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let(:unsorted) do
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[sorted[3], sorted[1], sorted[4], sorted[2],
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sorted[6], sorted[5], sorted[0], sorted[7]]
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end
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it 'sorts references by project and then by a given key' do
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expect(subject.sort(project1, unsorted)).to eq(sorted)
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end
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end
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end
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