replace is_member_of with member_of?

This commit is contained in:
Maxim Rydkin 2017-08-24 20:46:41 +03:00
parent 81061aef62
commit 90112f57d2
2 changed files with 10 additions and 10 deletions

View file

@ -244,11 +244,11 @@ Style/PerlBackrefs:
# NameWhitelist: is_a?
Style/PredicateName:
Enabled: true
Exclude:
- 'features/*'
# Exclude:
# - 'features/*'
# NamePrefix: is_
NamePrefixBlacklist: is_
NameWhitelist: has_n_stars
NameWhitelist: have_visible_content
# Offense count: 58
# Cop supports --auto-correct.

View file

@ -2,27 +2,27 @@ module SharedGroup
include Spinach::DSL
step 'current user is developer of group "Owned"' do
is_member_of(current_user.name, "Owned", Gitlab::Access::DEVELOPER)
member_of?(current_user.name, "Owned", Gitlab::Access::DEVELOPER)
end
step '"John Doe" is owner of group "Owned"' do
is_member_of("John Doe", "Owned", Gitlab::Access::OWNER)
member_of?("John Doe", "Owned", Gitlab::Access::OWNER)
end
step '"John Doe" is guest of group "Guest"' do
is_member_of("John Doe", "Guest", Gitlab::Access::GUEST)
member_of?("John Doe", "Guest", Gitlab::Access::GUEST)
end
step '"Mary Jane" is owner of group "Owned"' do
is_member_of("Mary Jane", "Owned", Gitlab::Access::OWNER)
member_of?("Mary Jane", "Owned", Gitlab::Access::OWNER)
end
step '"Mary Jane" is guest of group "Owned"' do
is_member_of("Mary Jane", "Owned", Gitlab::Access::GUEST)
member_of?("Mary Jane", "Owned", Gitlab::Access::GUEST)
end
step '"Mary Jane" is guest of group "Guest"' do
is_member_of("Mary Jane", "Guest", Gitlab::Access::GUEST)
member_of?("Mary Jane", "Guest", Gitlab::Access::GUEST)
end
step 'I should see group "TestGroup"' do
@ -35,7 +35,7 @@ module SharedGroup
protected
def is_member_of(username, groupname, role)
def member_of?(username, groupname, role)
@project_count ||= 0
user = User.find_by(name: username) || create(:user, name: username)
group = Group.find_by(name: groupname) || create(:group, name: groupname)