c5b3b71e89
Adds additional count param to Boards::Visits::LatestService
74 lines
2.2 KiB
Ruby
74 lines
2.2 KiB
Ruby
# frozen_string_literal: true
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require 'spec_helper'
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describe BoardGroupRecentVisit do
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let(:user) { create(:user) }
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let(:group) { create(:group) }
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let(:board) { create(:board, group: group) }
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describe 'relationships' do
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it { is_expected.to belong_to(:user) }
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it { is_expected.to belong_to(:group) }
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it { is_expected.to belong_to(:board) }
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end
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describe 'validations' do
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it { is_expected.to validate_presence_of(:user) }
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it { is_expected.to validate_presence_of(:group) }
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it { is_expected.to validate_presence_of(:board) }
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end
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describe '#visited' do
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it 'creates a visit if one does not exists' do
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expect { described_class.visited!(user, board) }.to change(described_class, :count).by(1)
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end
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shared_examples 'was visited previously' do
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let!(:visit) { create :board_group_recent_visit, group: board.group, board: board, user: user, updated_at: 7.days.ago }
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it 'updates the timestamp' do
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Timecop.freeze do
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described_class.visited!(user, board)
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expect(described_class.count).to eq 1
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expect(described_class.first.updated_at).to be_like_time(Time.zone.now)
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end
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end
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end
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it_behaves_like 'was visited previously'
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context 'when we try to create a visit that is not unique' do
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before do
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expect(described_class).to receive(:find_or_create_by).and_raise(ActiveRecord::RecordNotUnique, 'record not unique')
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expect(described_class).to receive(:find_or_create_by).and_return(visit)
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end
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it_behaves_like 'was visited previously'
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end
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end
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describe '#latest' do
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def create_visit(time)
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create :board_group_recent_visit, group: group, user: user, updated_at: time
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end
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it 'returns the most recent visited' do
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create_visit(7.days.ago)
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create_visit(5.days.ago)
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recent = create_visit(1.day.ago)
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expect(described_class.latest(user, group)).to eq recent
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end
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it 'returns last 3 visited boards' do
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create_visit(7.days.ago)
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visit1 = create_visit(3.days.ago)
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visit2 = create_visit(2.days.ago)
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visit3 = create_visit(5.days.ago)
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expect(described_class.latest(user, group, count: 3)).to eq([visit2, visit1, visit3])
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end
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end
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end
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