73 lines
2.7 KiB
Ruby
73 lines
2.7 KiB
Ruby
require 'spec_helper'
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describe TodosFinder do
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describe '#execute' do
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let(:user) { create(:user) }
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let(:project) { create(:project) }
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let(:finder) { described_class }
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before do
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project.add_developer(user)
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end
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describe '#sort' do
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context 'by date' do
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let!(:todo1) { create(:todo, user: user, project: project) }
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let!(:todo2) { create(:todo, user: user, project: project) }
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let!(:todo3) { create(:todo, user: user, project: project) }
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it 'sorts with oldest created first' do
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todos = finder.new(user, { sort: 'id_asc' }).execute
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expect(todos.first).to eq(todo1)
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expect(todos.second).to eq(todo2)
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expect(todos.third).to eq(todo3)
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end
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it 'sorts with newest created first' do
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todos = finder.new(user, { sort: 'id_desc' }).execute
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expect(todos.first).to eq(todo3)
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expect(todos.second).to eq(todo2)
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expect(todos.third).to eq(todo1)
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end
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end
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it "sorts by priority" do
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label_1 = create(:label, title: 'label_1', project: project, priority: 1)
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label_2 = create(:label, title: 'label_2', project: project, priority: 2)
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label_3 = create(:label, title: 'label_3', project: project, priority: 3)
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issue_1 = create(:issue, title: 'issue_1', project: project)
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issue_2 = create(:issue, title: 'issue_2', project: project)
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issue_3 = create(:issue, title: 'issue_3', project: project)
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issue_4 = create(:issue, title: 'issue_4', project: project)
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merge_request_1 = create(:merge_request, source_project: project)
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merge_request_1.labels << label_1
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# Covers the case where Todo has more than one label
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issue_3.labels << label_1
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issue_3.labels << label_3
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issue_2.labels << label_3
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issue_1.labels << label_2
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todo_1 = create(:todo, user: user, project: project, target: issue_4)
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todo_2 = create(:todo, user: user, project: project, target: issue_2)
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todo_3 = create(:todo, user: user, project: project, target: issue_3, created_at: 2.hours.ago)
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todo_4 = create(:todo, user: user, project: project, target: issue_1)
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todo_5 = create(:todo, user: user, project: project, target: merge_request_1, created_at: 1.hour.ago)
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todos = finder.new(user, { sort: 'priority' }).execute
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expect(todos.first).to eq(todo_3)
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expect(todos.second).to eq(todo_5)
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expect(todos.third).to eq(todo_4)
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expect(todos.fourth).to eq(todo_2)
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expect(todos.fifth).to eq(todo_1)
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end
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end
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end
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end
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